JEE Main Paper 2 Result 2019: The result of the JEE Main Paper 2 2019 has been released by the National Testing Agency (NTA) on Friday, February 1. Candidates who had appeared for the examination may check the official website-

At least two candidates scored 100 percentile in the exam. Laxmi Narayana Gollapudi and Raghunandan Reddy Gudla from Andhra Pradesh scored 100 NTA scores in Paper 2. The NTA had earlier declared the result of Paper 1 on January 19.

The notification along with the result stated that the scores have been normalised and the process of normalisation can be accessed in this document. Paper 2 is for B-Arch and B-Planning.

Steps to check JEE Main Paper 2 Result 2019:

Step 1: Visit the JEE Main official website-

Step 2: Click on the link to check the JEE Main Paper 2 Result 2019.

Step 3: Enter the application number, DoB, and security pin and click on ‘Login’.

Step 4: The scores will be displayed.

Step 5: Download and take a print out for future use.

A total number of 1.45 lakh candidates had appeared in the exam. JEE Main is conducted for admissions to IIT, NIT, RIT and other engineering colleges throughout the country. For admissions to IIT, JEE Advanced is conducted for candidates who clear the JEE Mains.

To be eligible to appear in the JEE Mains and Advanced, candidates must score at least 75 per cent (65 per cent for reserved category) in the class 12th board exam or be placed the in top 20th percentile of the results.