England captain Joe Root has named an unchanged team for the fifth and final Test against India starting at the Oval on Friday. Jonny Bairstow will keep wicket after recovering from a broken middle finger, while Alastair Cook will play in his 161st and final Test after announcing his retirement from international cricket. Also Read - I Have Imbibed Steve Smith's Art of Leaving Balls: Riyan Parag

Bairstow had his finger broken during the third Test which India won by 203 runs. The 28-year-old played solely as a batsman in England’s fourth-Test victory in Southampton, with Jos Buttler standing in as his wicketkeeping replacement. Also Read - Jos Buttler Raises Over £65,000 By Auctioning His 2019 ICC Cricket World Cup Final Jersey

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Speaking about the decision to give the gloves back to Bairstow, rather than sticking with Buttler, Root said, “We are very fortunate to be in a position where we have two quality keepers.””More than anything, they both want us to win games of cricket. There have been no issues or problems in that department,” he added.

Moeen Ali, the Man of the Match in Southampton, will continue at number three, where he was promoted ahead of Root in the fourth Test.

England have already secured a series victory and lead 3-1 heading into the final Test of the summer following a remarkable 60-run win last week at the Ageas Bowl.

England Playing XI: Alastair Cook, Keaton Jennings, Moeen Ali, Joe Root (c), Jonny Bairstow (w), Ben Stokes, Jos Buttler, Sam Curran, Adil Rashid, Stuart Broad, Jimmy Anderson.